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3 years ago

10

PLEASE HELP WILL MARL BRAINLIEST!!!!!!!!

2 answers:

7nadin3 [17]3 years ago

8 0

Answer:

c

Step-by-stepexplanation:

adell [148]3 years ago

7 0

Answer:

i believe the answer is a

i'm not sure...........

hope its right

:)

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MULTIPLE CHOICE

Nina [5.8K]

Answer:

-2,-2 minimum

Step-by-step explanation:

I just had a test on this

minimum because it is a minimum point it starts at the bottom

-2,-2 that is where the vertex is which is the point at the minimum

3 0

2 years ago

What is the solution to the system of equations below?

Alekssandra [29.7K]

(6,2) because X would equals 6 multiplied by 2 equals 12. Now minus 2 and that gives you a equilibrium of 10

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3 years ago

By treating savings as an ___ it guarantees that you will save the money instead of spending it

Mekhanik [1.2K]

Answer:

Money market account. I think.. not sure...

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

On the day of his 18th birthday harry decided to start saving money regularly

Veseljchak [2.6K]

We have been given that on the day of his 18th birthday Harry decided to start saving money regularly . Starting on that day, he could save 30.00 on the same date every month. We are asked to find the amount saved by the day before Harry's 60th birthday.

First of all, we will find years from 18 years to 60 years.

$\text{Years}=60-18=42$

We know that 1 year equals 12 months.

$\text{42 years}=12\times 42\text{ Months}=504\text{ Months}$

To find total amount saved, we will multiply 504 months by amount saved per month.

$\text{Total amount saved}=\$30\times 504$

$\text{Total amount saved}=\$15,120$

Therefore, Harry would have saved $\$15,120$ by the day before his 60th birthday.

3 0

3 years ago

Find the volume of the wedge with vertices at points (0,0,0), (1,0,0), (0,1,0), (0,0,1) by integrating the area of cross-section

Angelina_Jolie [31]

Answer:

V = 1/6 cubic units

Step-by-step explanation:

Applying the concept of integrals for volume calculation:

$V = \int\limits^b_a {S(x)} \, dx$ (1)

V = volume of the solid bounded by x = a and x = b

S(x) = cross section area of the solid, perpendicular to the x axis

From the figure we have that S is the area of a triangle that has base Z and height Y

Area of the triangle = $S(x)=\frac{y(x)*z(x)}{2}$ (2)

Calculation of y(x) and z(x)

We apply the equation of the point-slope line (plane xy):

Slope = $m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ (3)

Equation of the line = $y - y_{1} =m(x-x_{1} )$ (4)

Replacing the points (1,0) and (0,1) in (3):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (4):

$y-0=(-1)(x-1)$

y(x) = -x + 1 (Line A-B) (5)

We apply the equation of the point-slope line (plane xz):

Slope = $m = \frac{z_{2} - z_{1} }{x_{2} - x_{1}}$ (6)

Equation of the line = $z - z_{1} =m(x-x_{1} )$ (7)

Replacing the points (1,0) and (0,1) in (6):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (7):

$z-0=(-1)(x-1)$

z(x) = -x + 1 (Line A-C) (8)

Replacing (5) and (8) in (2)

$S(x) = \frac{(-x + 1) * (-x + 1)}{2} =\frac{(-x + 1)^{2} }{2}$ (9)

Replacing (9) in (1) and knowing that a = 0 and b = 1:

$V = \int\limits^1_0 {\frac{(-x + 1)^{2} }{2}} \, dx = \int\limits^1_0 {\frac{x^{2}-2x+1 }{2}} \, dx$

$V =\frac{1}{2} (\frac{x^{3} }{3} -2\frac{x^{2} }{2} +x)$ evaluated from x=0 to x=1

$V= \frac{1}{2} (\frac{1}{3} -1 +1) = \frac{1}{6}$

3 0

3 years ago