Answer:
the value of the t test statistic is - 3.419
Step-by-step explanation:
Given that;
n₁ = 18, u₁ = 78.3, s₁ = 6.4
n₂ = 11, u₂ = 84.3, s₂ = 5.3
α = 0.1
Now The hypothesis are;
H₀ : u₁ = u₂
H₁ : u₁ < u₂
To compute the value of the t test statistic;
t = [(x₁ - x₂) / s × √(1/n₁ + 1/n₂)]
where
s = √ [ ((n₁-1) × s₁² + (n₂ - 1 ) × s₂²) / ( n₁ + n₂ - 2)]
s = √ [ ((18-1) × 6.4² + (11 - 1 ) × 5.3²) / ( 18 + 11 - 2)]
s = √ [ (7 × 40.96 + 10 × 28.09 ) / 27 ]
s = √ [ (286.72 + 280.9) / 27 ]
s = √(567.62/27)
s = √21.0229
s = 4.585
Now t test statistics t = [(x₁ - x₂) / s × √(1/n₁ + 1/n₂)]
t = [(78.3 - 84.3) / 4.585 × √(1/18 + 1/11)]
t = -6 / (4.585 × 0.3827)
t = - 6 / 1.7546795
t = - 3.419
Therefore the value of the t test statistic is - 3.419
as as level of significance α = 0.1
df = 18+11-2 = 27
∴ T(csal) = t(0.1, 27) = -1.313
That is
t(statistics) < t(cal)
{ - 3.419 < -1.313 }
