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1 year ago

This level is locked because of this clock. Can you escape before its too late?

Mathematics

1 answer:

Taya2010 [7]1 year ago

7 0

Answer:

What do you want me to answer?

Step-by-step explanation:

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App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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2 years ago

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3 years ago

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Tomtit [17]

Answer:

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Step-by-step explanation:

First you have to add 4 by both sides, which will give you 8x<-32.

Then just divide both sides by 8 and you should get the same answer.

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2 years ago

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3 years ago

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Katen [24]

General Idea:

The quadratic function of the form $ax^2+bx+c=0$ .

Applying the concept:

Simplifying the equation in option A, we get...

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Simplifying the equation in option B, we get...

$B) \; \; (4a + 2)(2a - 1) + 1 = 0\\ Multiplying \; First \; \; Outer \; \; Inner \; \; Last \; terms\; in\; the \; left \; side.\\ \\ 4a \cdot 2a + 4a \cdot -1 + 2 \cdot 2a + 2 \cdot -1 + 1 = 0\\ \\ 8a^2-4a+4a-2+1=0\\ Combining \; like \; terms \; \\ \\ 8a^2 - 1 = 0\\ Above \; is \; a \; Quadratic \; Equation!$

Simplifying the equation in Option C, we get...

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Simplifying the equation in Option D, we get

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<u>Conclusion:</u>

Option B) & Option D) are quadratic equation!

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