Title:
<h2>The revenue will be maximum for 253 passengers.</h2>
Step-by-step explanation:
Let, the number of passenger is x, which is more than 194.
In this case, the travel agency will charge [312 - (x - 194)] per passenger.
The total revenue will be ![x[312 - (x - 194)] = 506x - x^{2}](https://tex.z-dn.net/?f=x%5B312%20-%20%28x%20-%20194%29%5D%20%3D%20506x%20-%20x%5E%7B2%7D)
.
As x is the variable here, we can represent the revenue function by R(x). Hence, 
.
The revenue will be maximum when 
.
Answer:
3^(-2y + 6) = (-2x+1)
Step-by-step explanation:
We have;
log_3_(-2x+1) = -2y + 6
What this means in exponential form is that;
3^(-2y + 6) = (-2x+1)
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Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.
