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dimaraw [331]
3 years ago
8

∠ACH = 115° ∠GBF = 35° What is the degree measure of ∠A?

Mathematics
2 answers:
fgiga [73]3 years ago
5 0

A straight line is 180°. So you can do:

∠ACH + ∠ACB = 180°  (you can do∠ACG or ∠ACB, doesn't matter)

This is because ∠ACH and ∠ACB make up a 180° angle(straight line)

∠ACH + ∠ACB = 180°  Since you know ∠ACH, you can plug it in

115° + ∠ACB = 180° Subtract 115 on both sides to find ∠ACB

∠ACB = 65°


The ∠GBF should be equal to ∠ABC, so ∠ABC = 35°

This is because opposite angles are congruent/identical (equal)


A triangle is also 180°.

Now that you know the angle of C and B, you can do this:

65° + 35° + ∠A = 180°

100° + ∠A = 180° Subtract 100 on both sides

∠A = 80°

nikdorinn [45]3 years ago
3 0

∠ACB is a Supplementary angle to ∠ACH. Supplementary angles must equal 180 degrees.

∠ACB = 180 - 115 = 65 degrees.


∠ABC is a vertical angle of ∠GBF, which means they are identical, so ∠ABC is 35 degrees.


The three inside angles of a triangle must equal 180 degrees.

∠A = 180 - 65 - 35 = 80 degrees

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Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

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Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

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c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

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Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

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For even samples: PosMe= n/2= 250/2= 125

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<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

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