Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
_____
<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
The mode is the value from a given set of data that occurs most often. It is the data with the highest frequency.
Given:
16,12,10,15,7,9,16
Form the above data given;
Rearranging for easy identification, we have;
7,9,10,12,15,16,16
From the above, we can deduce that the mode is 16 because it appears the most often. It appears twice.
Therefore, the mode is 16.
Answer:
Positive to negiative and they counded by 2s for the positive one and 6s for the negative one.
Step-by-step explanation:
Substitute -3 for x in f(x) = 2x^2 + 4x + 10:
f(-3) = 2(-3)^2 + 4(-3) + 10 = 18 - 12 + 10 = 16 (answer)
Answer:
The answer is C
Step-by-step explanation:
I took the test on Illuminate
