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Eduardwww [97]
3 years ago
10

Find the distance between 2-4i and d 6+i

Mathematics
1 answer:
liq [111]3 years ago
8 0

Answer:

7.211

Step-by-step explanation:

-For two points in the complex plane, the distance between the points is the modulus of the of the difference of the two complex numbers.

-Point 2-4i has the coordinates (2,-4)

-Point 6+i has the coordinates (6,1)

#We must find the distance between the two coordinates (2,-4) and (6,1):

=\sqrt{(6-2)^2+(1--4)^2}\\\\=\sqrt{4^2+6^2}\\\\=\sqrt{52}\\\\=7.211

Hence, the distance between the two points is 7.211

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Jan's average score after fifteen tests was 82. Her average on the next five tests was 90. What was her average score for all tw
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Answer:

86

Step-by-step explanation:

82+90=172

172/2 (divided by two because thats how many numbers we added up to get 172)

172/2=86

86 is your answer

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What is 5 over 1-6 in the form of a and b
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What is one extensive and one intensive property of marker ink?
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3 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
PLEASEEEE HELPPP
soldier1979 [14.2K]
Ik I’m not know help but gee I forgot this just go on google
4 0
3 years ago
Read 2 more answers
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