Without measuring, how can you determine whether two sides of a polygon are congruent?

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Ow... this geometry is sure hard!!
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Wait a second. Nope.
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TWO SIDES!!
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ITT!!
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CONVERSE ITT!!
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Converse Isosceles Triangle Theorem!
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Look at the picture I attached.
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Two angles equal... THE SIDES ADJACENT TO IT EQUAL!!
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PERFECTO!!
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Hope I helped!!

Source: I am learning Honors Geometry, near end of course.

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What is the measure of

posledela

The triangle is isosceles so m∠A and m∠C are the same.

So to find ∠B, we do 74 + 74 + b = 180

148 + b = 180
b = 180 - 148
b = 32

Answer B is the right choice.

3 0

3 years ago

#12 with explanation please

4vir4ik [10]

Answer:

30.01 units

Step-by-step explanation:

Given vertices WXYZ:

W(-4,5), X(2,4), Y(3, -4), Z(-1, -6)

Perimeter is the sum of the side length.

Use distance formula to find each side:

WX = $\sqrt{(2+4)^2+(4-5)^2} =\sqrt{37}$ ≈ 6.08
XY = $\sqrt{(3-2)^2+(-4-4)^2} =\sqrt{65}$ ≈ 8.06
YZ = $\sqrt{(-1-3)^2+(-6+4)^2} =\sqrt{20}$ ≈ 4.47
WZ = $\sqrt{(-1+4)^2+(-6-5)^2} =\sqrt{130}$ $\sqrt{(-1+4)^2+(-6-5)^2}=\sqrt{130}$ ≈ 11.40