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3 years ago

Without measuring, how can you determine whether two sides of a polygon are congruent?

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Ow... this geometry is sure hard!!
.
Wait a second. Nope.
.
TWO SIDES!!
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ITT!!
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CONVERSE ITT!!
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Converse Isosceles Triangle Theorem!
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Look at the picture I attached.
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Two angles equal... THE SIDES ADJACENT TO IT EQUAL!!
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PERFECTO!!
.
Hope I helped!!

Source: I am learning Honors Geometry, near end of course.

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zubka84 [21]

Answer:

1/24

Step-by-step explanation:

1/4 x 1/3 x 1/2 x 1/1

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2 years ago

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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1 year ago

Free pionts for brainlist pleas

meriva

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3 years ago

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Ugo [173]

Answer:

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Step-by-step explanation:

square root of 121 is 11

so each side of the square is 11

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3 years ago

Sarah made a deposit of $100 into a savings account with 3

Andru [333]

Answer: D, $116

Step-by-step explanation:

A = 100(1 + 0.03)^5

A = 100(1.03)^5

A = 100(1.1593)

A = 115.92

Hope this helped!

7 0

2 years ago