If she leaves 15 minutes earlier than Allen, she would have to drive at 56.47 mph to arrive at the same time as Amber
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more number and variables.
Amber travels at a speed 60 mph, hence the time taken (t) is:
60 = 240/t
t = 4 hours
If he leaves 15 minutes earlier, the time would be 4 hr + 0.25 hr (15 min) = 4.25 hr, hence:
Speed = 240 miles / 4.25 hr = 56.47 mph
If she leaves 15 minutes earlier than Allen, she would have to drive at 56.47 mph to arrive at the same time as Amber
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Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
$810 !! hope this helps :)
Answer:
1 008.56628 US$ kkkkkkkkkk
If we know that Laura's canvas is square, and one side is 22cm,
area of a square is l*w, with a special case of l=w
the area will be
A= l*w=22*22=484cm^2
also, Asquare is=l^2
