Answer:
740
Step-by-step explanation:
The n th term of an arithmetic series is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then
a₁ + 2d = 7 → (1)
a₁ + 6d = 23 → (2)
Subtract (1) from (2) term by term
4d = 16 ( divide both sides by 4 )
d = 4
Substitute d = 4 into (1)
a₁ + 2(4) = 7
a₁ + 8 = 7 ( subtract 8 from both sides )
a₁ = - 1
The sum to n terms of an arithmetic series is
= 
[ 2a₁ + (n - 1)d ] , thus
= 
[ (2 × - 1) + (19 × 4) ]
= 10(- 2 + 76) = 10 × 74 = 740
Answer:It's the last option again. You have 1 linear factor (3x) and 2 copies of a quadratic factor (x² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Step-by-step explanation:
Fun U Needa Write An Equation For This Aint Gon Help In The Future
Answer:
Step-by-step explanation:
L=2W
P=2(L+W), using L=2W this becomes
P=2(2W+W)
P=2(3W)
P=6W, given P=150
6W=150
W=25, and since L=2W
L=50 so
L=50ft and W=25ft
You have to combine like numbers
y-4x-1(1-6x)+3y+x
4y -4x-(1-6x)+x
4y - 4x - 1 + 6x + x
4y + 3x - 1
