The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
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Hello,
P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5
Answer:
Alone?
Step-by-step explanation:
Was this a rhyme or a problem? but 833 x 54 = 44,982.
(D) 4 shaded for every 2 unshaded! Hope this helps! :)
Commutative says you can add or multiply in any order
basically goes like this
a+b=b+a or
ab=ba
so what we need is something where the order change, nothing else
first one: (4+3)+x=(3+4)+x, the order changed, correct
2nd
ab=ba, this is not addition
3rd
r+(s+t)=(r+s)+t this is associative property
4th
n+0=n
this is zero addition property
answer is first one
