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3 years ago

9

Ms. Marvin is buying pencils for her class. she has a total of 22 students, and she wants to give each student 2 pencils. pencil

s come in packs of 12. how many packs will she need to purchase to have enough?

1 answer:

dimaraw [331]3 years ago

7 0

Answer:

4

Step-by-step explanation:

first 22x2=44

44÷12= 3 2/3

round up= 4

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Question 2 of 10

Veronika [31]

Answer:

D

Step-by-step explanation:

Use the general formula of quadratic equation:

$x_{1,2}=\dfrac{-b \pm\sqrt{b^2-4ac} }{2a} = \dfrac{6\pm\sqrt{36-40}}{4}=\dfrac{6\pm2i}{4} = \dfrac{3\pm i}{2}$

Thus we choose D

8 0

2 years ago

June has $1.95 in dimes and nickels. She has a total of 28 coins. How many of each type of coin does she have.

Verdich [7]

A dime = 0.10

A nickel = 0.05

N + D = 28 coins

Rewrite this as N = 28 -D

0.10D + 0.05N = 1.95

Replace N withe the rewritten equation above:

0.10D + 0.05(28-D) = 1.95

Use the Distributive Property:

0.10D + 1.4 - 0.05D = 1.94

Add the like terms:

0.05D + 1.4 = 1.95

Subtract 1.4 from both sides:

0.05D = 0.55

Divide both sides by 0.05

D = 0.55 / 0.05

D = 11

Nickels = 28 - 11 = 17

There are 11 dimes and 17 nickels.

3 0

3 years ago

Read 2 more answers

a spool holds 6.75 meters and a craft club buys 21 spools. what is the total cost if the ribbons costs 2 dollars per meter?

Burka [1]

● To do this, you need to multiply 6.75 by 21 to find out how many meters are in all. 6.75×21 is 141.75

● Next you multiply 141.75 by 2 to see how much it costs which is 283.5

● Since we're dealing with money, it would have two place values so we add a zero and we get $283.50

3 0

3 years ago

The table of a linear function is partially completed below. What is the missing y-value to complete the table?

NeTakaya

The missing answer would be -2

4 0

3 years ago

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Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai

Nina [5.8K]

Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

Given : Confidence level : $(1-\alpha)=0.90$

⇒ significance level = $\alpha= 0.10$

z-value for 90% confidence interval (using z-table)= $z_{\alpha/2}=1.645$

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

Now, the required sample size will be :

$n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2$

Simplify , we get

$n=(0.25)(6765.0625)=1691.265625\approx1692$

Hence, the required sample size = 1692

8 0

3 years ago

Read 2 more answers