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arsen [322]
3 years ago
11

I am having trouble with these equations 7x + 2y = - 8 8y = 4x solve using substitution

Mathematics
1 answer:
dybincka [34]3 years ago
5 0
X = -1 y = -0.5
7 times -1 = -7.
2 times -0.5 = -1, -1+-7= -8
8y= -4, 4x= -4,
Hope this helps!
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For number 7 the answer should be 20%. 10 is 50% and the other 6 is 30%.
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A student obtain 85 ,90,95,100and 75 in his maths test (1). What is the average of his test grades?
netineya [11]

Answer:

89.

Step-by-step explanation:

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Help! this is hard :(( (10 points) :c
Cerrena [4.2K]
If I understand correctly, just substitute 15 for C in f = 1.8c + 32, then solve for F
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f=<span><span>(1.8)(15)</span>+<span>32
</span></span>------------
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3 years ago
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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
Darya [45]

Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

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