R + 3 = 2

First, subtract 3 from both sides. / Your problem should look like: r = 2 - 3
Second, simplify 2 - 3 to -1. / Your problem should look like: r = -1

Answer: r = -1

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3 years ago

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37. ABC has vertices A(0, 0) , B(0, 4) , and C(3, 0) . Write the equation for the line containing the altitude overline AR in st

Nutka1998 [239]

Answer:

3x - 4y = 0

Step-by-step explanation:

The triangle Δ ABC has vertices A(0,0), B(0,4) and C(3,0).

Therefore, the equation of the straight line BC in intercept form will be

$\frac{x}{3} + \frac{y}{4} = 1$

⇒ 4x + 3y = 12

⇒ $y = - \frac{4}{3}x + 4$ .......... (1)

This is a equation in slope-intercept form and the slope is $- \frac{4}{3}$ .

Now, the altitude AR is perpendicular to equation (1) and hence its slope will be $\frac{3}{4}$ .

{Since, the product of slope of two mutually perpendicular straight line is always - 1}

Therefore, the equation of the altitude AR which passes through A(0,0) will be

$y = \frac{3}{4}x$

⇒ 4y = 3x

⇒ 3x - 4y = 0 (Answer)

4 0

3 years ago