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3 years ago

PLEASE I NEED HELP FOR THIS QUICKLY!

Mathematics

2 answers:

pantera1 [17]3 years ago

7 0

24/55 is the answer decimal form is 0.436

sweet-ann [11.9K]3 years ago

5 0

Answer:

24/55

Step-by-step explanation:

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In a southern state, it was revealed that 5% of all automobiles in the state did not pass inspection. what is the probability th

Jobisdone [24]

Fortune Battle Royale

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3 years ago

Can you please help me solve this?

oee [108]

So, i would use the add the two equation method, so add those to get:
2e=-4
e=-2
then plug in e to get d, so d+-2=1
d=3
plug into the other one to make sure
-3+-2=-5
so it would be (3,-2)

8 0

3 years ago

A chef planning for a large banquet thinks that 2 out of every 5 dinner guests will order soup. 800 guests are going to be at th

Xelga [282]

Answer:

The Chef will prepare 320 soups for a large banquet

Step-by-step explanation:

chef thinks that 2 out of every 5 dinner guests will order soup

===> Order soup / total number of attender

= 2/5

Total guest = 800 ==> 4 people ordered soup is

2 /5 = x /800

cross multiplying

x = 2 x 800 / 5

= 320

The Chef will prepare 320 soups for a large banquet

8 0

4 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

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3 years ago

Question 1. If X= {prime numbers less than 13} Y = {odd numbers less than 21} (i). List the members of X and Y (ii). List the me

valkas [14]

Step-by-step explanation:

easy union means all the element from small to big

8 0

2 years ago