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katen-ka-za [31]
3 years ago
6

Antuan deposited $2590 into a 3 year CD at an interest rate of 2.3% compounded quarterly.

Mathematics
1 answer:
lora16 [44]3 years ago
7 0

Answer:

the interest rate is $183.89 =~ $ 184

Step-by-step explanation:

In this question, Antuan deposited $2590 into a 3 year CD (Certificate of Deposit)  at an interest rate of 2.3% compounded quarterly. We need to find the interest account earned after 3 years.

Formula used will be :

Interest = P ( 1 + r/n) ^ n ^ t - P

Where

P= Principal amount

r= interest rate (in decimals)

n= no of times the interest is compounded

t = no of years

Here we are subtracting P because we only need interest amount and not the future value.

Using this formula and finding the value will be:

P= $2590

r = 2.3 % or 0.023

n = 4

t = 3

Interest = 2590 * ( 1 - 0.023 / 4) ^ 4^ * ^ 3 - 2590

Interest= 2590 (1.071) -2590\\Interest= 2773.89 - 2590\\Interest= 183.89

So the interest rate is $183.89 =~ $ 184

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Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist
satela [25.4K]

Answer:

t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539    

p_v =2*P(t_{(9)}>1.539)=0.158  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis.  

Step-by-step explanation:

Data given and notation  

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation given by:

s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And we got:

\bar X=7.55 represent the sample mean

s=0.103 represent the sample standard deviation

n=10 sample size  

\mu_o =7.5 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 7.5  

Alternative hypothesis:\mu \neq 7.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=10-1=9  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(9)}>1.539)=0.158  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis.  

3 0
3 years ago
Convert 15 degree Celsius into Fahrenheit
bogdanovich [222]

Answer:

59 ° F

Step-by-step explanation:

F = 9/5 C + 32

 = 9/5 (15) + 32 = 59 °  F

8 0
1 year ago
Consider the following data set:
Komok [63]

Answer:

+5 Range; The range is now 25

Step-by-step explanation:

The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.

3 0
3 years ago
3) An archer applies an average force of 200 N to draw the bow string back 1.3 m.
Schach [20]

Step-by-step explanation:

W=N•D

W=(200)(1.3)

W= 260

3 0
2 years ago
A. 0.27 and 0.50
defon

Answer:

Part 1

a. .27 < .50

b. .33 < .75

c. 4.60 > 3.89

d. .76 > .08

e. .09 < .11

f. 3.33 > 3.30

Part 2

.27(2)= .54

.50(1)= .50

.27(2)= .54 is larger than .50 because if it was money, .54 is greater than .50

Step-by-step explanation:

3 0
3 years ago
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