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suter [353]
3 years ago
13

NP and QS are parallel line.

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

QRT and POM

D is the answer

Step-by-step explanation:

Inessa05 [86]3 years ago
3 0

Answer:

Step-by-step explanation:

∠QRT and ∠POM are alternate exterior angles

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Write 2.484848... as a mixed number in simplest form.
NeX [460]

Step-by-step explanation:

step 1. x = .484848 . . . repeats

step 2. 100x = 48.48484848 . . . (multiply by 100)

step 3. subtract x from 100x : 99x = 48

step 4. x = 48/99 (now add the 2 back in)

step 5. answer: 2-48/99.

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3 years ago
A suit is on sale for $154. If the original price of the suit was $440, what percent was discounted for the sale?
9966 [12]
The dollar amount of the discount is 440 - 154 = $286.
Therefore the percentage discount for the sale is given by:
\frac{286}{440}\times100=65\ percent
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4 years ago
Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
makkiz [27]

Answer:

9a + 6b and 5c - 3d

Step-by-step explanation:

(a)

4a + 7b + 5a - b ← collect like terms

= (4a + 5a) + (7b - b)

= 9a + 6b

(b)

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3 0
3 years ago
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zzz [600]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.
evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}

b) P(population with IQ between 120 and 125.)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%

P(120 \leq x \leq 125) = 4.4\%

6 0
3 years ago
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