Question

Flying against the wind, an airplane travels 3060 kilometers in 3 hours. Flying with the wind, the same plane travels 7560 kilometers in 6 hours. What is the rate of the plane in still air and what is the rate of the wind ?

Answer 1

Answer:

The speed of plane against wind S 1 = 1020 kmph     And

The speed of plane with wind S 2      = 1260 kmph

Step-by-step explanation:

Given as :

The distance of airplane against the wind = D 1 = 3060 km

The time taken in against the wind             = T 1 = 3 hours

The distance of airplane with the wind       = D 2 = 7560 km

The time taken in with the wind                   = T 2 = 6 hours

Now, Speed of plane against the wind = $\frac{Distance}{Time}$

So,  S 1 =  $\frac{D 1}{T 1}$

Or,   S 1 =  $\frac{3060}{3}$ = 1020 kmph

Similarly

Speed of plane with the wind    = $\frac{Distance}{Time}$

Or,    S 2 =  $\frac{D 2}{T 2}$

Or,     S 2 =  $\frac{7560}{6}$ = 1260 kmph

Hence The speed of plane against wind S 1 = 1020 kmph     And

            The speed of plane with wind S 2      = 1260 kmph   Answer