All categories

3 years ago

What fraction of a ton is equivalent to 1,000 pounds

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

1/2 ton would be the correct answer since a single ton is 2,000 lbs

You might be interested in

+ 2x + 12y + 4<br><br> What are the coefficients of this expression?

Tanzania [10]

Answer:

The coefficients are: 2, 12, 4.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two

Vikentia [17]

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

$Y \sim P( \beta = 2)$

the probability mass function can be represented as follows:

$\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}$

where;

y = 0,1,2,3 ...

Hence, the probability of no defects in 10 feet of steel

y = 0

$\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}$

$\mathtt{P(y =0) = \dfrac{0.1353 \times 1}{1}}$

P(y =0) = 0.1353

4 0

2 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Xy = –16. What is the constant of variation for this relationship?

olganol [36]

Direct variation is y=kx and inverse variation is y=k/x, in this case:

y=-16/x

So this is an inverse variation with a constant of -16

6 0

3 years ago

A rug is 12 feet wide and 15 1/2 feet long. What is the area of the rug?

fgiga [73]

Answer:

372 feet^2

Step-by-step explanation:

A=LW

A=(15 1/2)(12)=(31/2)(12)=(31/2)(24/2)=744/2=372

3 0

3 years ago