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murzikaleks [220]
3 years ago
6

Simplify 6 cm : 1.5 m

Mathematics
1 answer:
Zolol [24]3 years ago
4 0

6cm=0.06m

0.06m : 1.5m

6m : 150m

1m : 35m

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Find the values of x and y. Pls helpI’m helpless at math
Svetradugi [14.3K]

Answer:

  • x = 1
  • y=\frac{\sqrt{3}}{2}  

Step-by-step explanation:

From the given right-angle triangle

The angle = ∠60°

  • The adjacent to the angle ∠60° is 1/2.
  • The opposite to the angle ∠60° is y.

The hypotenuse = x

<u>Determining the value of x:</u>

Using the trigonometric ratio

cos 60° = adjacent / hypotenuse

substituting adjacent = 1/2 and hypotenuse = x

cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}

\cos \left(60^{\circ \:}\right)=\frac{1}{2x}

\frac{1}{2}=\frac{1}{2x}          ∵ cos (60°) = 1/2

2x=2

Dividing both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Thus, the value of hypotenuse x is:

x = 1

<u>Determining the value of y:</u>

Using the trigonometric ratio

sin 60° = opposite / hypotenuse

As we have already determined the value of hypotenuse x = 1

substituting opposite = y and hypotenuse = 1

sin 60° = y/1

y = 1 × sin 60°

y=\frac{\sqrt{3}}{2}       ∵  \sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}

Therefore, the value of y is:

y=\frac{\sqrt{3}}{2}      

Summary:

  • x = 1
  • y=\frac{\sqrt{3}}{2}    
5 0
3 years ago
What is the difference between an equation with a variable and an inequality with a variable?
NeX [460]

Answer:

An equation is a statement that maintains the equal value of two mathematical expressions. If the statement is true for all variable values, it is called an identity. ... An equation shows the equality of two variables while an inequality shows the inequality of two variables

7 0
3 years ago
What does it mean to get paid royalty
Savatey [412]

Answer:

A royalty is a payment made by one party (the licensee or franchisee) to another that owns a particular asset (the licensor or franchisor), for the right to ongoing use of that asset. ... A royalty interest is the right to collect a stream of future royalty payments.

Step-by-step explanation:

5 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
20.) Using the cross multiplication method, which of the following is the solution to 18/6x = 4/(x+3)?
Likurg_2 [28]

Answer:

B. 9

Step-by-step explanation:

7 0
2 years ago
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