X: # of pairs of socks; y: # of blouses
Then $2.99x+$12.99y=$43.92.
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Answer:
y=3÷9
Step-by-step explanation:
2x-9y=11
or,2×7-9y=11
or,14-11=9y
or,3÷9=y
Answer:
10
Step-by-step explanation:
4 x 5 = 20
= 10
Answer:
Only the given table represents a function. Option 1 is correct.
Step-by-step explanation:
A relation is called a function, if there exist a unique value of y for each value of x. It means for each input there exist a unique output.
A function is always a relation but all relations are not function.
In the given table for each value of x, we have unique value of y, therefore the given table represents a function.
In second relation, at x=-2, the values of y are y=10 and y=-7. For single x, there are more than one value of y, therefore the second relation is not a function.
In third relation, at x=6, the values of y are y=-2 and y=1. For single x, there are more than one value of y, therefore the third relation is not a function.
