Y=5x I think. Hope this helps
Answer:
B
Step-by-step explanation:
If you arrange a statistics in order from least to greatest, the middle number is the median.
If there is even number of numbers in a list, let it be n numbers, then we take the average of n/2th and n/2 + 1 th terms.
Here, all of them have 6 numbers, so 6/2 = 3 and 4th, we take average of 3rd and 4th number to find the median.
Since they are arrange in order we check each:
Jon = average of 6 and 7, (6+7)/2 = 6.5
Leroy = average of 6 and 8, (6+8)/2 = 7
Simon = average of 5 and 6, (5+6)/2 = 5.5
Leroy's median is the greatest (7).
Answer:
When a trinomial is in the form of ax2 + bx + c, where a is a coefficient other than 1, look first for common factors for all three terms. Factor out the common factor first, then factor the remaining simpler trinomial. If the remaining trinomial is still of the form ax2 + bx + c, find two integers, r and s, whose sum is b and whose product is ac.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
Given the variables
Y: standardized history test score in third grade.
X₁: final percentage in history class.
X₂: number of absences per student.
<em>Determine the following multiple regression values.</em>
I've estimated the multiple regression equation using statistics software:
^Y= a + b₁X₁ + b₂X₂
a= 118.68
b₁= 3.61
b₂= -3.61
^Y= 118.68 + 3.61X₁ - 3.61X₂
ANOVA Regression model:
Sum of Square:
SS regression: 25653.86
SS Total: 36819.23
F-ratio: 11.49
p-value: 0.0026
Se²= MMError= 1116.54
Hypothesis for the number of absences:
H₀: β₂=0
H₁: β₂≠0
Assuming α:0.05
p-value: 0.4645
The p-value is greater than the significance level, the decision is to not reject the null hypothesis. Then at 5% significance level, there is no evidence to reject the null hypothesis. You can conclude that there is no modification of the test score every time the number of absences increases one unit.
I hope this helps!
Suppose

is even, i.e. there is some integer

such that

. Then

where

is just some other integer. Therefore

is odd, proving the contrapositive, and so the original statement is also true.