Question

A company receives equipment from two factories: 38% from factory A, and all other equipment from factory B. Each factory has a percentage of equipment that is defective: 1% of factory A's equipment is defective, while 4% of factory B's equipment is defective. If a piece of the company's equipment is selected at random, what is the probability that it is defective and from factory B?a. 0.0248b. 0.0038c. 0.6012d. 0.6600

Answer 1

Answer:

Probability will be 0.0286 which is nit given in the bellow option

So none of the given option is correct

Explanation:

We have given that company receives equipment from company A is 38 %

So $p(A)=0.38$

And rest of the equipment is received from company B

So $p(B)=1-0.38=0.62$

It is given that the equipment which is received from company A is 1 % defective

So $p(D/A)=0.01$

And equipment which is received from company B is 4 % are defective

So $p(D/B)=0.04$

So the probability that the equipment is defective $=p(A)\times p(D/A)+p(B)\times p(D/B)=0.38\times 0.01+0.62\times 0.04=0.0286$

So none of the option is correct