3 years ago

Factor the expression completely over the complex numbers. y^4+24y^2+144

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:

Correct Answer:

((y+2i√3) (y-2i√3))^2

Step-by-step explanation:

Just took the test and this is the right answer.

Svetllana [295]3 years ago

6 0

25y^6 +144

I think this is right :)

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dezoksy [38]

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$A" = (3,2)\ \ B" = (-1,1)\ \ C" =(-3,4)\ \ D =(-1,4)$

Step-by-step explanation:

Given [Missing]

$A = (-3,4)$

$B = (1,3)$

$C =(3,6)$

$D =(1,6)$

The first transformation: reflection across the y-axis.

The rule is: $(x,y)==>(-x,y)$

So:

$A = (-3,4)$ ==> $A' = (3,4)$

$B = (1,3)$ ==> $B' = (-1,3)$

$C =(3,6)$ ==> $C' = (-3.6)$

$D =(1,6)$ ==> $D' = (-1,6)$

Translation 2 units down

The rule is: $(x,y)==>(x,y-2)$

So:

$A' = (3,4)$ ==> $A" =(3,4-2) =(3,2)$

$B' = (-1,3)$ ==> $B" = (-1,3-2) = (-1,1)$

$C' = (-3.6)$ ==> $C" = (-3,6-2) = (-3,4)$

$D' = (-1,6)$ ==> $D" =(-1,6-2) = (-1,4)$

Hence:

$A" = (3,2)\ \ B" = (-1,1)\ \ C" =(-3,4)\ \ D =(-1,4)$

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