If the discriminant of a quadratic equation, given by B^2-4AC is positive, it has 2 real solutions. If 0, it has 1 real solution and if negative it has 0 real solutions.
Answer:
a = 14
Step-by-step explanation:
Given
9 + a = 23 ( subtract 9 from both sides )
a = 14
-- They're losing employees . . . so you know that the line will slope down, and
its slope is negative;
-- They're losing employees at a steady rate . . . so you know that the slope is
the same everywhere on the line; this tells you that the graph is a straight line.
I can see the function right now, but I'll show you how to go through the steps to
find the function. I need to point out that these are steps that you've gone through
many times, but now that the subject pops up in a real-world situation, suddenly
you're running around in circles with your hair on fire screaming "What do I do ?
Somebody give me the answer !".
Just take a look at what has already been handed to you:
0 months . . . 65 employees
1 month . . . . 62 employees
2 months . . . 59 employees
You know three points on the line !
(0, 65) , (1, 62) , and (2, 59) .
For the first point, 'x' happens to be zero, so immediately
you have your y-intercept ! ' b ' = 65 .
You can use any two of the points to find the slope of the line.
You will calculate that the slope is negative-3 . . . which you
might have realized as you read the story, looked at the numbers,
and saw that they are <u>firing 3 employees per month</u>.
("Losing" them doesn't quite capture the true spirit of what is happening.)
So your function ... call it ' W(n) ' . . . Workforce after 'n' months . . .
is <em>W(n) = 65 - 3n</em> .
Answer:
Your teacher is right, there is not enough info
Step-by-step explanation:
<h3>Question 1</h3>
We can see that RS is divided by half
The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS
So P is not on the perpendicular bisector of RS
<h3>Question 2</h3>
We can see that PD⊥DE and PF⊥FE
There is no indication that PD = PF or ∠DEP ≅ FEP
So PE is not the angle bisector of ∠DEF
Answer:
(2,7) is not a solution to the given system of equations.
Step-by-step explanation:
Given system of equation is:
2x + 3 = y
2x + y = 15
To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.
Putting x=2 and y=7 in Eqn 1
2(2) + 3 = 7
4 + 3 = 7
7 = 7
Thus the ordered pair satisfies the equation
Putting x=2 and y=7 in Eqn 2
2(2) + 7 = 15
4 + 7 = 15
11 ≠ 15
The ordered pair do not satisfy the second equation.
Hence,
(2,7) is not a solution to the given system of equations.
