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liraira [26]
3 years ago
6

Look Please"/--------

Mathematics
2 answers:
Hatshy [7]3 years ago
8 0

Answer:

80

Step-by-step explanation:

i did 12*6 then i did 2*4 then i add the products

elixir [45]3 years ago
5 0

Answer:

80

Step-by-step explanation:

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If a mechanic uses his credit card to pay for a compressor that costs $477.95 and does not pay on it until the second month, wha
Rina8888 [55]

Answer:

A. $7.17

Step-by-step explanation:

We have been given that a mechanic uses his credit card to pay for a compressor that costs $477.95 and does not pay on it until the second month.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nT} where,

A = Final amount after T years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Periods of compounding,

T = Time in years.

Let us multiply our given rate by 12 to get APR and convert it in decimal form.

APR=12\times 1.5\%

APR=18\%

18\%=\frac{18}{100}=0.18

Since 1 year equals 12 months, so 1 month will be 1/12 year.  

Upon substituting our given values in above formula we will get,

A=477.95(1+\frac{0.18}{12})^{12\times\frac{1}{12}}

A=477.95(1+0.015)^{1}

A=477.95(1.015)

A=485.11925

Now let us subtract principal amount from the final amount to get the monthly interest charge at the end of 1st month.

\text{The monthly interest charge be at the end of the first month}=485.11925-477.95

\text{The monthly interest charge be at the end of the first month}=7.16925\approx 7.17

Therefore, the monthly interest charge be at the end of the first month will be $7.17 and option A is the correct choice.

4 0
3 years ago
Solve 2x + 5y = 20; 3x - 10y = 37 by elimination. How do you do this? Thank-you!
mr Goodwill [35]

\left\{\begin{array}{ccc}2x+5y=20&\text{multiply both sides by 2}\\3x-10y=37\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+10y=40\\3x-10y=37\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=77\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=11}\\\\\text{Put the value of x to the first equation:}\\\\2(11)+5y=20\\\\22+5y=20\qquad\text{subtract 22 from both sides}\\\\5y=-2\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{2}{5}}\\\\Answer:\ \boxed{x=11\ and\ y=-\dfrac{2}{5}}

6 0
3 years ago
Keiquan is calculating his net worth. He has listed these items: $50 rare baseball card, $15 cash, $10 owed for lunch, $25 in sa
V125BC [204]
An asset is what you have that is worth value the $10 for school lunch wouldn't be an asset because it is a debt
5 0
3 years ago
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Five more than a number tripled is half the number. What is the number?
Alina [70]
The equation:
let x represent the unknown number
5+y3=x*05 (or x divided by 2)
y represents the tripled number and x represents the end result. Hope this helps!
8 0
3 years ago
Read 2 more answers
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
3 years ago
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