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Montano1993 [528]
3 years ago
7

Help me with these 3 questions please. aH-

Mathematics
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer:

1) 2/7; 43; 3/7

2) C

3) 30; 30; 10; is not; 10; is not

Step-by-step explanation:

1) y + 4/7 = 6/7

y = 6/7 - 4/7

y = 2/7

17 + b = 60

b = 60 - 17

b = 43

6/7 = m + 3/7

m = 6/7 - 3/7

m = 3/7

2) 11.5 - x = 5.25

x = 11.5 - 5.25

x = 6.25

3) he can substitute 30 for t.

He can then multiply ⅓ by 30 to get a product of 10 (⅓ × 30 = 10).

Since 15 is not equal to 10, Harry's solution is not correct

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Triss [41]
1. By combining like terms
2. Same variable = same term, so you can combine them
3. Because 2y - y = 1y , and 1y is the same as y because a y is one y (obviously)
4. 1/2 + 1/2 = 1. A half an x and a half an x makes one whole x, therefore, x
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Hopefully these are right, I’m a bit rusty!
6. 4x
7. 3y
8. y - 4.5
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8 0
3 years ago
Find the following algebra, I am in class and plz give explanation
Lelechka [254]

1) Solving 4a+4b-ac-bc we get (a+b)(4-c)

2) Solving 16a^4-8b we get 8(2a^4-b)

3) Solving x^2-8x+15 we get (x-3)(x-5)

Step-by-step explanation:

We need to solve the following expressions:

1) 4a+4b-ac-bc

We will solve this expression by factoring common terms:

4a+4b-ac-bc

Factoring 4 from 4a+4b and -c from -ac-bc

4(a+b)-c(a+b)

Taking common term

(a+b)(4-c)

2) 16a^4-8b

We will solve this expression by factoring common terms:

16a^4-8b

Taking 8 as common term:

8(2a^4-b)

3) x^2-8x+15

We can solve the expression by breaking the middle term into 2

x^2-3x-5x+15\\Finding\,\,common:\\=x(x-3)-5(x-3)\\=(x-3)(x-5)

Keywords: Finding factors

Learn more about Finding factors at:

  • brainly.com/question/10771256
  • brainly.com/question/1332667
  • brainly.com/question/1357167

#learnwithBrainly

6 0
3 years ago
Evaluate the expression when x = 6
ivolga24 [154]

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76

4+2×6×6(x=6)

4+72

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3 years ago
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zheka24 [161]
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8 0
2 years ago
Linear equations 3(x+1)=3x+3
vaieri [72.5K]
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3 0
3 years ago
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