Answer:
(4,0)
Step-by-step explanation:
The object is first at (0,0)
It is reflected across line x=-2, this means you draw the mirror line at x=-2 and count 2 equal units backwards to get the image.The image will be at ;
The image (-4,0) is then reflected on the y-axis
You know reflection on the y-axis, the y-coordinate remains the same but the x-coordinate is changed to its opposite sign.
Hence;
(- -4,0)= (4,0)
The image will move 8 units towards positive x-axis.This is the same as moving 4 units from the mirror line at (0,0) and land at (4,0)
I'll do the math for this, it may take me a few minutes so i will update this comment with an answer in just a minute. I always get anxious when nobody replies kind of quickly as i feel it is being forgotten. So just a heads up i'm working on a answer!
You know this is just a formula, right?
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
33
Step-by-step explanation:
im not sure actually
