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julia-pushkina [17]
3 years ago
8

Fator by grouping ab+2a+5b+10

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0
Ab + 2a + 5b + 10

= a(b + 2) + 5(b + 2)

= (b + 2) (a + 5)
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3 years ago
Work out the formula for the nth term of the<br>quadratic sequence:<br>5, 11, 19, 29​
Sladkaya [172]

Answer:

n squared + 3n + 1

Step-by-step explanation:

5,11,19,29

Firstly look at the difference between each number. The first difference is 6 then 8 then 10 etc. After that you look at your created sequence - 6,8,10 etc. The difference is 2 each time. Then applying rules, you have to do the constant difference divided by 2 to get a coefficient of n squared. So in this case it's n squared because 2/2 = 1 so you don't have to place a 1 in front of the n squared. After you create a sequence from the n squared. That would be 1,4,9 etc. Then you need to see how to get from the sequence: 1,4,9 etc to your original sequence: 5,11,19 etc. So if you calculate it you will get 4,7,10 because firstly 5-1 = 4 then 11-4 = 7 etc. The sequence 4,7,10 is a linear sequence so the constant difference is 3 each time. So to get a nth term of a linear sequence you will start off as 3n then you will substitute 1 then 2 then 3 into the 3n. Therefore that would be 3,6 etc. So if you take the first substituted term, that would be 3 as said before then you will have to see how to get from the 3 to 4 so that is just adding 1. So the nth term of this linear sequence is 3n + 1. Check if it works at the end. So the overall nth term of the quadratic sequence is n squared as said before + 3n + 1.

8 0
3 years ago
Some people think it is unlucky if the 13th day of a month falls on a Friday. Show that in every calendar year (non leap or leap
MakcuM [25]
We will set a variable, d,  to represent the day of the week that January starts on.  For instance, if it started on Monday, d + 1 would be Tuesday, d + 2 would be Wednesday, etc. up to d + 6 to represent the last day of the week (in our example, Sunday).  The next week would start over at d, and the month would continue. For non-leap years:
If January starts on <u>d</u>, February will start 31 days later.  Following our pattern above, this will put it at <u>d</u><u> + 3</u> (28 days would be back at d; 29 would be d+1, 30 would be d+2, and 31 is at d+3).  In a non-leap year, February has 28 days, so March will start at <u>d</u><u>+3</u> also.  April will start 31 days after that, so that puts us at d+3+3=<u>d</u><u>+6</u>.  May starts 30 days after that, so d+6+2=d+8.  However, since we only have 7 days in the week, this is actually back to <u>d</u><u>+1</u>.  June starts 31 days after that, so d+1+3=<u>d</u><u>+4</u>.  July starts 30 days after that, so d+4+2=<u>d</u><u>+6</u>.  August starts 31 days after that, so d+6+3=d+9, but again, we only have 7 days in our week, so this is <u>d</u><u>+2</u>.  September starts 31 days after that, so d+2+3=<u>d</u><u>+5</u>.  October starts 30 days after that, so d+5+2=d+7, which is just <u>d</u><u />.  November starts 31 days after that, so <u>d</u><u>+3</u>.  December starts 30 days after that, so <u>d</u><u>+5</u>.  Remember that each one of these expressions represents a day of the week.  Going back through the list (in numerical order, and listing duplicates), we have <u>d</u><u>,</u> <u>d,</u><u /> <u>d</u><u>+1</u>, <u>d</u><u>+2</u>, <u>d+3</u><u>,</u> <u>d</u><u>+3</u>, <u>d</u><u>+3</u>, <u>d</u><u>+4</u>, <u>d</u><u>+5</u>, <u>d</u><u>+5</u>, <u /><u /><u>d</u><u>+6</u><u /><u /> and <u>d</u><u>+6</u>.  This means we have every day of the week covered, therefore there is a Friday the 13th at least once a year (if every day of the week can begin a month, then every day of the week can happy for any number in the month).  
For leap years, every month after February would change, so we have (in the order of the months) <u></u><u>d</u>, <u>d</u><u>+3</u>, <u>d</u><u>+4</u>, <u>d</u><u />, <u>d</u><u>+2</u>, <u>d</u><u /><u>+5</u>, <u>d</u><u />, <u>d</u><u>+3</u>, <u>d</u><u /><u>+6</u>, <u>d</u><u>+1</u>, <u>d</u><u>+4</u>, a<u />nd <u>d</u><u>+</u><u /><u /><u>6</u>.  We still have every day of the week represented, so there is a Friday the 13th at least once.  Additionally, none of the days of the week appear more than 3 times, so there is never a year with more than 3 Friday the 13ths.<u />
5 0
3 years ago
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