Solve this in an equality 8z+3-2z <51

1 answer:

5 0

Answer: x < 8

8z+3-2z<51

Collect like terms.

6z+3<51

Move constant to the right side and change its sign.

6z<51-3

Subtract the numbers.

6z<48

Divide both sides of the inequality by 6.

z < 8

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Nadia finds out her favorite horse family population is increasing at a constant rate. The horse family was at 24 in 2011 and is

pogonyaev

Answer:

The equation is p = (8/3) t + 24

In 2020, we will have about 48 horses.

Step-by-step explanation:

In 3 years the family increased by 32 - 24 = 8.

So the constant of proportionality = 8/3.

The required equation is p = (8/3)tx + 24

where p = the population and t is the number of years after 2011.

So in 2020 we can predict that in 2020 the number of horses

= (8/3) * 9 + 24

= 72/3 + 24

= 24 + 24

= 48.

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Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0

Leviafan [203]

Answer: We do not reject the null hypothesis.

Step-by-step explanation:

When the p-value is greater than the significance level , then we do not reject the null hypothesis or if p-value is smaller than the significance level , then we reject the null hypothesis.

Given : Test statistic : $z = -2.28$

Significance level : $\alpha=0.02$

By using the standard normal distribution table ,

The p-value corresponds to the given test statistic ( two tailed ):-

$2P(Z>|z|)=2P(Z>2.28)=0.0226$

Since the p-value is greater than the significance level of 0.02.

Then , we do not reject the null hypothesis.

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3 years ago

Simplify the radical

mamaluj [8]

Answer:

$9d^3$

Step-by-step explanation:

$~~~\sqrt{81 d^6}\\\\=\left(81 d^6 \right)^{\tfrac 12}\\\\=\left(81\right)^{\tfrac 12} \cdot \left(d^6 \right)^{\tfrac 12}\\\\=\left(9^2 \right)^{\tfrac 12} \cdot d^{\tfrac 62}\\\\=9d^3$