Answer:
6 cms.
Step-by-step explanation:
If the side of an equilateral triangle is 2x cm then its height is √3x and its base is 2x.
Area = 1/2 * base * height
9√3 = 1/2 * 2x * √3x
9√3 = x * √3x
9 = x^2
x = 3
So length of each side = 2*3 = 6.
x = 9
Let us recall parallelogram properties, which states that opposite angles of parallelogram are congruent.
We can see from graph that side US is parallel to TR and measure of angle U equals to measure of angle R, therefore, quadrilateral drawn in our given graph is a parallelogram.
Since we know that opposite sides of parallelogram are congruent. In our parallelogram UT=SR and US=TR.
In our triangle STU and triangle TSR side TS=TS by reflexive property of congruence.
Therefore, our triangles are congruent by SSS congruence.
The 3-D shape would be created if the figure was rotated around the x-axis is a cone
<h3>What are 3-D shapes?</h3>
3-D shapes (short form of 3-Dimensional shapes) are shapes that have width, length and height
<h3>How to determine the 3-D shape?</h3>
The coordinates are given as:
(0, 0), (-3, -4) and (-3, 0)
When the above coordinates are plotted on a coordinate plane and the points are connected;
We can see that the points form a right-triangle
See attachment for the shape
As a general rule
Rotating a right-triangle across the x-axis would form a cone
Hence, the 3-D shape would be created if the figure was rotated around the x-axis is a cone
Read more about rotation at:
brainly.com/question/4289712
#SPJ1
Step-by-step explanation:
3
Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].
Therefore, by mid-point formula:
4 (a)
Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:
is the equation of line AB.
Now we have to check whether C(4, 7) lie on line AB or not.
Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.
Hence, point C (4, 7) lie on the straight line AB.
4(b)
Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.