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Vsevolod [243]
3 years ago
11

explain the difference bewtween adding with base ten blocks and subtracting with base ten blocks. relate it to the rules of addi

tion and subtraction.
Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0
The difference between subtracting 10 blocks is taking them away from your total. And adding them is getting more than your actual total.




Hope that helped.
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10.
Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

\mu population mean  

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=83-1=82

The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=62.132

\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

3 0
3 years ago
Devin is playing a game with 3 bonus rounds. In the first bonus round he gets 2 times the points, in the second bonus round he g
kirill [66]
X+2x+3x+4x=9x. x is a variable that represents the number of points he won so far
7 0
3 years ago
How do I solve (fraction) 2/3d=1/6?
IgorLugansk [536]

Answer:

  d = 1/4

Step-by-step explanation:

Multiply the equation by the inverse of the coefficient of the variable.

\dfrac{2}{3}d=\dfrac{1}{6}\\\\\dfrac{3}{2}\cdot\dfrac{2}{3}d=\dfrac{3}{2}\cdot\dfrac{1}{6}\\\\d=\dfrac{3\cdot 1}{2\cdot 6}=\dfrac{3}{12}=\dfrac{3\cdot 1}{3\cdot 4}\\\\d=\dfrac{1}{4}

8 0
3 years ago
What is 24.21 written in expanded form?
vodomira [7]

Answer:

(2 x 10) + (4 x 1) + (2 x 0.1) + (1 x 0.01)

Step-by-step explanation:

4 0
3 years ago
Please help me out with the odds on this one (IMPORTANT) *determine whether the given relation is a function*
Hitman42 [59]

Answer:

It's not a function.

Step-by-step explanation:

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3 years ago
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