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stiv31 [10]
3 years ago
6

It’s 500 seconds or eight minutes greater

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
The answer is 500 seconds it’s 5.33 minutes.
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(02.04 MC)
borishaifa [10]

Answer:

umm idk let me get back to you

Step-by-step explanation:

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3 years ago
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You buy 70 of your favorite songs from a Web site that charges ​$0.98 for each song. What is the cost of 70 ​songs? Use mental m
Leya [2.2K]

Answer: If this isn't a trick question it is $68.60

Step-by-step explanation: You just multiply the 98 cents by the 70 songs.

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2 years ago
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(a) If G is a finite group of even order, show that there must be an element a = e, such that a−1 = a (b) Give an example to sho
Dahasolnce [82]

Answer:

See proof below

Step-by-step explanation:

First, notice that if a≠e and a^-1=a, then a²=e (this is an equivalent way of formulating the problem).

a) Since G has even order, |G|=2n for some positive number n. Let e be the identity element of G. Then A=G\{e} is a set with 2n-1 elements.

Now reason inductively with A by "pairing elements with its inverses":

List A as A={a1,a2,a3,...,a_(2n-1)}. If a1²=e, then we have proved the theorem.

If not, then a1^(-1)≠a1, hence a1^(-1)=aj for some j>1 (it is impossible that a^(-1)=e, since e is the only element in G such that e^(-1)=e). Reorder the elements of A in such a way that a2=a^(-1), therefore a2^(-1)=a1.

Now consider the set A\{a1,a2}={a3,a4,...,a_(2n-1)}. If a3²=e, then we have proved the theorem.

If not, then a3^(-1)≠a1, hence we can reorder this set to get a3^(-1)=a4 (it is impossible that a^(-1)∈{e,a1,a2} because inverses are unique and e^(-1)=e, a1^(-1)=a2, a2^(-1)=a1 and a3∉{e,a1,a2}.

Again, consider A\{a1,a2,a3,a4}={a5,a6,...,a_(2n-1)} and repeat this reasoning. In the k-th step, either we proved the theorem, or obtained that a_(2k-1)^(-1)=a_(2k)

After n-1 steps, if the theorem has not been proven, we end up with the set A\{a1,a2,a3,a4,...,a_(2n-3), a_(2n-2)}={a_(2n-1)}. By process of elimination, we must have that a_(2n-1)^(-1)=a_(2n-1), since this last element was not chosen from any of the previous inverses. Additionally, a_(2n1)≠e by construction. Hence, in any case, the statement holds true.

b) Consider the group (Z3,+), the integers modulo 3 with addition modulo 3. (Z3={0,1,2}). Z3 has odd order, namely |Z3|=3.

Here, e=0. Note that 1²=1+1=2≠e, and 2²=2+2=4mod3=1≠e. Therefore the conclusion of part a) does not hold

7 0
3 years ago
It took Kathy 8 minutes to run a mile. It took her 48 minutes to run 5 miles. How many times as long did it take Kathy to run th
kotykmax [81]
Divide 48 by 8. Therefore 6 times.
4 0
3 years ago
Write the algebraic expression for each word problem. See if you can spot the trick problem that doesn’t need algebra!
AfilCa [17]

Answer:

6) -7 + 10 = 3 (3 more; total number doesn't matter)

7) 50w + 20

8) c / 5

9) 5 + 2t

10) 4d  + 2d

I didn't see the trick problem!

7 0
3 years ago
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