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3 years ago

12

Apply the distributive to a factor out the greatest common factor 64 + 40

1 answer:

NikAS [45]3 years ago

8 0

Factors of 64:

1 2 4 8 16 32 64

Factors of 40:

1 2 4 5 8 10 20 40

8 is the GCF

8(8+ 5)

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Kamila [148]

Answer:

n=5, m = 4

Step-by-step explanation:

It is a parallelogram so m+8 = 3m and 2n-1 = 9

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3 years ago

Rewrite the equation from part A by factoring tge side that contains the variable r. Part A: 3r-6

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Step-by-step explanation:

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3 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

4 years ago

PLEASE HELP ME TO SOLVE THIS QUESTION WITH STEP-BY-STEP. THANK YOU!!!

Alexeev081 [22]

Answer:

Can u show the whole question

5 0

3 years ago

Read 2 more answers

If the angles of a triangle are (2y - 5)degrees, (y + 20)degrees, and (3y-5) degrees what are the values of the angles

NNADVOKAT [17]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \sf{51.68 \: , \: 48.34 \:, \: 80.02}}}}$ </h3>

Step-by-step explanation:

Let's solve:

As we know that the sum of angles of traingle adds to 180°

$\sf{2y - 5 + y + 20 + 3y - 5 = 180}$

Collect like terms

⇒ $\sf{6y - 5 + 20 - 5 = 180}$

⇒ $\sf{6y + 15 - 5 = 180}$

⇒ $\sf{6y + 10 = 180}$

Move constant to right hand side and change it's sign

⇒ $\sf{6y = 180 - 10}$

Calculate the difference

⇒ $\sf{6y = 170}$

Divide both sides of the equation by 6

⇒ $\sf{ \frac{6y}{6} = \frac{170}{6} }$

Calculate

⇒ $\sf{y = 28.34}$

Now, let's replace the value:

⇒ $\sf{2y - 5 = 2 \times 28.34 - 5 = 51.68}$

⇒ $\sf{y + 20 = 28.34 + 20 = 48.34}$

⇒ $\sf{3y - 5 = 3 \times 28.34 - 5 = 80.02}$

Hope I helped!

Best regards!!

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3 years ago

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