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valentinak56 [21]
3 years ago
14

On a map, if one centimeter represents 25 kilometers, how many kilometers does 7 centimeters represent?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

x = 175 km

Step-by-step explanation:

We can use ratios to solve this problem.  Put the map distance over the real life distance.

1 cm      7 cm

--------  = ---------

25 km    x km

Using cross products.

1 * x = 7 * 25

x = 175 km

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coldgirl [10]

Answer: The probability of finding a white individual among the progeny if you cross these two animals is ¼.

Step-by-step explanation: Since these two animals are heterozygous black animals (Bb), crossing Bb x Bb will produce offsprings that are black (¾) and white (¼).

The first B will meet with the second B to form a BB (Black) progeny.

The first B will meet with the second b to form Bb (Black) progeny.

Likewise, the first b will meet with the first B to form Bb (Black) progeny.

Lastly, the first b will meet with the second b to form bb (white) progeny.

These are the possible progeny from the cross between Bb and Bb. Therefore, the probability of having white offspring is ¼.

6 0
3 years ago
2/(11/16 +3) I know the answer is 12/29. I just don't know how to get there
kodGreya [7K]
11/6+3 is 29/6. 2/(29/6) is 12/29, which is the answer.
3 0
4 years ago
Pls help; I will mark brainliest!
anzhelika [568]

Answer:

20 inches

Step-by-step explanation:

15 =(3/4)x

15/(.75)=20

4 0
4 years ago
Read 2 more answers
What is the exact perimeter of kite ? Show your work.
Afina-wow [57]

Answer:

<u>The perimeter of the kite is 29 units.</u>

Step-by-step explanation:

1. Let's use the Pythagorean Theorem to find the perimeter of the kite:

With the information given, we have four right triangles with a new point A, intersecting UW and VX. Those triangles are:

Δ UVA

Δ VWA

Δ UXA

Δ XWA

As we can see in the figure, length of UV and VW is the same and the length of UX and WX is also the same.

2. Let's find the value of UV and VW

UV is the hypotenuse of Δ UVA and it sides are 3 and 4 units length. So, we can calculate the length of UV this way:

Length of UV ² = UA ² + VA ²

Replacing with the real values:

Length of UV ² = 3 ² + 4 ²

Length of UV ² = 9 + 16

Length of UV ² = 25

√Length of UV ² = √25

<u>Length of UV  = 5 units ⇒ Length of VW = 5 units</u>

3. Let's find the value of UX and WX

UX is the hypotenuse of Δ UXA and it sides are 3 and 9 units length. So, we can calculate the length of UX this way:

Length of UX ² = UA ² + XA ²

Replacing with the real values:

Length of UX ² = 3 ² + 9 ²

Length of UX ² = 9 + 81

Length of UV ² = 90

√Length of UV ² = √90

<u>Length of UV  = 9.5 units (rounding to the nearest tenth) ⇒ Length of WX= 9.5 units</u>

<u>4. </u>Let's calculate the perimeter of the kite:

Perimeter of the kite = UV + VW + WX + UX

Perimeter of the kite = 5 + 5 + 9.5 + 9.5

<u>Perimeter of the kite = 29 units</u>

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3 years ago
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