Answer:
TS=QV
Step-by-step explanation:
To prove SAS congruence, you need to prove that two lines and the angle between them are all respectively equal.
In the diagrams we already have RS=WV and ∠RST=∠WVQ, so it follows that we need to prove that TS=QV.
Answer as an inequality: 
Answer in interval notation: 
Answer in words: Set of positive real numbers
All three represent the same idea, but in different forms.
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Explanation:
Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is 
For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.
Because of this,
has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.
The domain of
is x > 0 which in interval notation would be
. This is the interval from 0 to infinity, excluding both endpoints.
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The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.
So,

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.
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In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.
Let D = difference between mean and median of data.
Mean = (22 + 8 + 10 + 18 + 12 + 20)/6
Mean = 90/6
Mean = 15
Let m = median
m = 8, 10, 12, 18, 20, 22
m = (12 + 18)/2
m = 30/2
m = 15
D = M - m
D = 15n- 15
D = 0
Answer:
x = 3 or x = 1
Step-by-step explanation:
Solve for x over the real numbers:
x^2 - 4 x + 3 = 0
Subtract 3 from both sides:
x^2 - 4 x = -3
Add 4 to both sides:
x^2 - 4 x + 4 = 1
Write the left hand side as a square:
(x - 2)^2 = 1
Take the square root of both sides:
x - 2 = 1 or x - 2 = -1
Add 2 to both sides:
x = 3 or x - 2 = -1
Add 2 to both sides:
Answer: x = 3 or x = 1
y = 2x - 3
for x = 0 → y = 2(0) - 3 = -3 → (0, -3)
for x = 2 → y = 2(2) - 3 = 1 → (2, 1)
y = -2x + 5
for x = 0 → y = -2(0) + 5 = 5 → (0, 5)
for x = 2 → y = -2(2) + 5 = 1 → (2, 1)
Answer: A. (2, 1)