Explanation:
ur answer okkkkkkkkkkkkkkkkll
Answer:
The answer is 17.03052. We assume you are converting between grams Ammonia and mole.
Reaction: 2K₍s₎ + 2H₂O₍l₎ → 2KOH₍aq₎ + H₂₍g₎.
K - potassium.
H₂O - water.
KOH - potassium-hydroxide.
H₂ - hydrogen.
s - solid phase.
l - liquid.
aq - disolves in water.
g - gas.
Reaction is exothermal (release of energy) and potassium burns a purple flame. H<span>ydrogen released during the reaction reacts with </span>oxygen<span> and ignites.</span><span>
</span>
5.4 M = moles of solute / 1.50 L
<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>
<span>8.1 mol = moles of solute </span>
In a reduction reaction,
some electrons are gained by the substance being reduced. The balanced
half-reaction to this would be:
<span>MnO2(s) + 4 H+ (aq)
+ 2e ---> Mn^2+ (aq) + 2 H2O
(aq)</span>
<span>It is called balanced reaction
since the number of each element in the left side is equal to the number of
each element on the right side.</span>
