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3 years ago

At 298 K, oxygen (O2) and ozone (O3) have different properties because their

Chemistry

1 answer:

Paha777 [63]3 years ago

5 0

Answer: (3) molecules have different molecular structures.

Explanation:

1) Oxygen (O₂) and ozone (O₃) are allotropes of each other.

2) Allotropes are different structural forms of a same element with different structures and properties, when they are in the same state: solid, liquid, gas.

3) The bonds is what define the structure and properties of the substances, so since O₂ has only two bonds and O₃ has three bonds, the properties and behaviors of the element are different.

4) Other example of allotropes are graphite and diamond: two different forms of carbon. Both, graphite and diamond are formed only by carbon atoms, but they are bonded differently so, as you know, diamond and graphite have different properties: graphite is very soft while diamond is one of the hardest known substances.

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Using appropriate chemical equation distinguish between cation and anion hydrolysis

harina [27]

Answer:

HCO3- (aq) + H2O (I) <--> H2CO3 (aq) + OH- (aq)

Explanation:

The equation to distinguish between cation and anion hydrolysis is given below :

HCO3- (aq) + H2O (I) <--> H2CO3 (aq) + OH- (aq)

The important thing to remember is their origin. The anions can react with water and can produce hydroxide ions while hydroxide ions make a solution basic.

5 0

3 years ago

Tap water at room temperature has a pH of 7.2 and carbonate alkalinity of 200 mg/L (= 40 mmol/L). What is the concentration of b

UNO [17]

Answer:

the concentration of bicarbonate is [HCO₃⁻] = 0,03996 M and carbonate is [CO₃²⁻] = 3,56x10⁻⁵ M.

Explanation:

Carbonate-bicarbonate is:

HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25

Using Henderson-Hasselbalach formula:

pH = pka + log₁₀ $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$

7,2 = 10,25 + log₁₀ $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$

8,91x10⁻⁴ = $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$ (1)

Also:

0,040 M = [CO₃²⁻] + [HCO₃⁻] (2)

Replacing (2) in 1:

[HCO₃⁻] = 0,03996 M

Thus:

[CO₃²⁻] = 3,56x10⁻⁵ M

I hope it helps.

4 0

3 years ago

Write the net ionic equation for any precipitation reaction that may be predicted when aqueous solutions of calcium iodide and c

Hitman42 [59]

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

$3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)$

Ionic form of the above equation follows:

$3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)$

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)$

Hence, the net ionic equation is written above.

8 0

3 years ago

The relationship between pressure and volume, when moles and temperature of a gas are held constant, is: PV = k. We could say th

pochemuha

You can say that if the volume of the gas is halved, the pressure is doubled.

The expression shows that pressure and volume are inversely proportional if temperature and amount of gas is held constant. This means that if volume goes down the pressure needs to go up. That also means that in order to maintain the K value, if pressure is doubled the volume needs to be halved and if the pressure is halved the volume needs to be doubled.

This relationship only works if we assume everything else (Temperature and moles of gas) to be constant.

7 0

3 years ago

Ionic compound of GaTe

kow [346]

Answer:

Gallium(II) telluride

Explanation:

3 0

3 years ago