Answer:
The answer should be 1000 kg / m3
Answer:
(See explanation for further details)
Explanation:
1) The quantity of moles of sulfur is:


2) The number of atoms of helium is:


3) The quantity of moles of carbon monoxide is:


4) The number of molecules of sulfur dioxide is:


5) The quantity of moles of sodium chloride is:


6) The number of formula units of magnesium iodide is:


7) The quantity of moles of potassium permanganate is:


8) The number of molecules of carbon tetrachloride is:


9) The quantity of moles of aluminium is:


10) The number of molecules of oxygen difluoride is:


Molar mass RbMnO₄ = 204.40 g/mol
1 mole ---------- 204.40 g
7.88 mole ------ ?
mass = 7.88 * 204.40 / 1
mass = 1610.672 g
hope this helps!
Answer:
At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.
Explanation:
Given data:
At volume = ?
Mass of NaOH = 12.5 g
Molarity of solution = 0.540 M
Solution:
First of all we will calculate the number of moles of sodium hydroxide.
Number of moles = mass/molar mass
Number of moles = 12.5 g / 40 g/mol
Number of moles = 0.3125 mol
Volume of NaOH:
Molarity = number of moles / volume in L
Now we will put the values.
0.540 M = 0.3125 mol / volume in L
volume in L = 0.3125 mol / 0.540 mol/L
volume in L = 0.58 L