The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057
Answer:
- vertical scaling by a factor of -4
- horizontal translation 5 units left
- vertical translation 11 units up
Step-by-step explanation:
We notice that the multiplier of the squared term in f(x) is 0.5; in g(x), it is -2, so is a factor of -4 times that in f(x).
If we scale f(x) by a factor of -4, we get ...
-4f(x) = -2(x -2)² -12
In order for the squared quantity to be x+3, we have to add 5 to the value that is squared in f(x). That is, x -2 must become x +3. We have to replace x with (x+5) to do that, so ...
(x+5) -2 = x +3
The replacement of x with x+5 amounts to a translation of 5 units to the left.
We note that the added constant after our scaling changes from +3 to -12. Instead, we want it to be -1, so we must add 11 to the scaled function. That translates it upward by 11 units.
The attached graph shows the scaled and translated function g(x):
g(x) = -4f(x +5) +11
Answer:
17 3.14
/30
Step-by-step explanation:
Short answer : x = -13/3
But let's solve your equation step-by-step.
-2(x+8)=4x+10
Step 1: Simplify both sides of the equation.
(Distribute)
Step 2: Subtract 4x from both sides
Step 3: Add 16 to both sides.
Step 4: Divide both sides by -6.
Answer:
x = -13/3