Answer:
Option B is the correct choice.
Step-by-step explanation:
The graph is attached below.
We have to find the
intercept meaning the value of the point on
when ![y=0](https://tex.z-dn.net/?f=y%3D0)
So we will put the value of zero
instead of
in our given equation.
So here we have solved it algebraically.
![y=\frac{3}{4}x-3](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B4%7Dx-3)
Putting ![y=0](https://tex.z-dn.net/?f=y%3D0)
![0=\frac{3}{4}x-3](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B3%7D%7B4%7Dx-3)
![0=\frac{3x-12}{4}](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B3x-12%7D%7B4%7D)
Multiplying
both sides.
![0=3x-12](https://tex.z-dn.net/?f=0%3D3x-12)
Adding
both sides.
![12=3x](https://tex.z-dn.net/?f=12%3D3x)
Dividing with
both sides.
![x=\frac{12}{3}=4](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B12%7D%7B3%7D%3D4)
So the x-intercept of the given equation is
which can be written as
in terms of coordinates.
Option B
is the correct choice.
Vertex form of a parabola
<span>y = a (x - h)^2 + k </span>
<span>where (h, k) is the vertex </span>
Substituting the values of h and k.
we get,
<span>y = a(x + 4)^2 + 2 </span>
<span>substituting in the point (0, -30) for x and y
</span><span>-30 = a (0 + 4)^2 + 2
</span>solve for a,
<span>-30 = 16 a + 2 </span>
<span>-32 = 16 a </span>
<span>-2 = a </span>
<span>y = -2(x + 4)^2 + 2 </span>
<span>Put y = 0 </span>
<span>-2 x^2 - 16 x - 30 = 0 </span>
<span>-2(x^2 + 8 x + 15) = 0 </span>
<span>x^2 + 8 x + 15 = 0 </span>
<span>(x + 3)(x + 5) = 0 </span>
<span>x = -3
x = -5</span>
Answer:
Step-by-step explanation:
first solve for y=mx+ b format
y-3= 1/2(x+2)
y-3= 1/2x+1
y= 1/2x+4
slope is 1/2; y-intercept is 4