The true statement is (d) none of the above
<h3>Missing information</h3>
I. P(3 and tail)
II. P(even and head)
III .P(odd and head)
<h3>How to determine the equivalent probabilities?</h3>
We start by calculating each probability
<u>I. P(3 and tail) </u>
There is only one 3 in the 5 numbers.
So:
P(3) = 1/5
The probability of a tail in a coin is:
P(Coin) = 1/2
So, we have:
P(3 and tail) = 1/5 * 1/2
P(3 and tail) = 1/10
<u>II. P(even and head) </u>
There are three even numbers in the 5 numbers.
So:
P(even) = 3/5
The probability of a head in a coin is:
P(head) = 1/2
So, we have:
P(even and head) = 3/5 * 1/2
P(even and head) = 3/10
<u>III .P(odd and head)</u>
There are two odd numbers in the 5 numbers.
So:
P(odd) = 2/5
The probability of a head in a coin is:
P(head) = 1/2
So, we have:
P(odd and head) = 2/5 * 1/2
P(even and head) = 1/5
By comparing the results, none of the probabilities are equal.
Hence, the true statement is (d) none of the above
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is divided by
the remainder is 11 (option D is correct). To find the remainder after division by
you have to use another synthetic division. Actually,
then the remainder is 119 (option C is false).
the expression
is
and
(option A is correct). You cannot state the same when
(option B is false).
nor
because the remainders in both cases are not equal to 0 (options E and F are false).