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sweet-ann [11.9K]
3 years ago
14

Here is a classic riddle: Mr. Smith has an apple orchard. He hires his daughter, Lucy, to pick apples and offers her two payment

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

I am so confused

Step-by-step explanation:

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Find a polynomial P(x) with the zeros x=2, −(2), √3, −√3
Zigmanuir [339]

Answer:

P(x) = x^{4} - 7x² + 12

Step-by-step explanation:

Given zeros x = 2, x = - 2, x = \sqrt{3}, x = - \sqrt{3}

Then the factors are (x - 2), (x + 2), (x - \sqrt{3} ), (x + \sqrt{3} )

and the polynomial is the product of the factors, that is

P(x) = (x - 2)(x + 2)(x - \sqrt{3} )(x + \sqrt{3} ) ← expand in pairs using FOIL

      = (x² - 4)(x² - 3) ← distribute

     = x^{4} - 3x² - 4x² + 12 ← collect like terms

    = x^{4} - 7x² + 12

6 0
2 years ago
Mia has 12 boxes of cookies. Each box contains 36 cookies. she has another 258 cookies in the pantry. How many cookies does she
lana66690 [7]

690

12×36 + 258 = 690 For extending to 20 characters

8 0
2 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
2 years ago
I really need help I have 20 minutes
nlexa [21]

Answer:

a. -1.7

b. -1.2

c. -0.5

d. 0.6

e. 1.1

Step-by-step explanation:

7 0
2 years ago
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Simplify by multiplying <br><br> (5x-2)(3x+4)
Stells [14]

Answer:

15x - 8

Step-by-step explanation:

hope it helps

5 0
2 years ago
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