25g = 25,000 g=1000 im doing math homework and need help asap!
2 answers:
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Answer:
The correct options are;
EFGH has 4 congruent sides
Diagonal FH bisects angles EFG and EHG
Angle FEH is congruent to angle FGH
Step-by-step explanation:
1) Given that for a reflection, we have;
The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection
Therefore;
The distance of the point E from the line HF = The distance of the point G from the line HF
Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)
We can show that from the length of a line given by the equation, that the length EH ≅ GH and EF ≅ GF
Therefore since we are given that EH = EF, we have;
EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides
2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;
ΔEHF ≅ ΔGHF
∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent
Similarly, ∠GFH ≅ ∠EFH
Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF
Therefore, diagonal FH bisects angles EFG and EHG
3) Given that ΔEHF ≅ ΔGHF, we have;
Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent
Answer:
a. The amount Taylor will need to finance is $8,000
b. The amount Taylor pays as interest in one year is $400
Step-by-step explanation:
The given parameters of the financing for the car are;
The cost of the car Taylor plans to purchase, C = $10,000
The amount Taylor has saved to be used as down payment, S = $2,000
The interest rate of the credit Taylor is offered = 5%
The duration given for repayment of the loan = 5 years
a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;
P = C - S
∴ P = $10,000 - $2,000 = $8,000
b. The amount of interest on the loan in one year, 'I', is given by the following formula;
Where;
I = The interest payed
P = The principal amount taken as loan = $8,000
R = The interest rate = 5% APR
T = The time period the interest is applied = 1 year
Plugging in the values, we get;
The interest Taylor will pay on the loan in one year, I = $4,00