Question

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Answer 1

Answer:

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* Lets explain how to solve the problem

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = $\frac{60*20}{100}= 12$

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = $\frac{60*25}{100}= 15$

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = $\frac{60*30}{100}= 18$

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = $\frac{60*50}{100}= 30$

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.