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mote1985 [20]
3 years ago
14

devin is making a candle by pouring melted wax into a mold in the shape of a square pyramid. Each side of the base of the pyrami

d is 30 mm and the height of the pyramid is 18mm. to get the wax for the candle, devin melts blocks of wax that are each 8 mm by 6mm by 5mm. how many of the wax cubes will devin need in order to make the candle? show all formulas and calculations ​
Mathematics
1 answer:
likoan [24]3 years ago
4 0

Answer:

(1/3)(9*9*10)=270cm^3 pyramid volume

270/(4*4*4)=4.22cubes

round

5 wax cubes

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-6 1/10=-14+c how do I solve​
horsena [70]

Answer:

c = 7 9/10

Step-by-step explanation:

-6 1/10=-14+c

-14+c = -61/10

-14+c +14= -61/10 +14

c = 7 9/10

I hope it's right

3 0
3 years ago
Which expression is equivalent to 36 + 24?
rosijanka [135]

Answer:

D

Step-by-step explanation:

12(3+2). Use the Distribuitive Property.

12*3 = 36

12*2 = 24.

12(3+2) = 36 + 24

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Mr. Stanton bought 2.6 yards of fabric for $8.94. About how much was the cost per yard?
lapo4ka [179]

In order to find CPU (Cost per unit) we must take the cost, and divide it by the number of units.

So,

\$8.94\div2.6=\$3.4384

Since we are talking about money, it is implied to round to the nearest cent, so the final answer is

$3.44

4 0
4 years ago
Find the missing side length.
MaRussiya [10]

x = 6

Explanation:

use the pythagorean theorem which is <u>a^2 + b^2 = c^2</u>. 8 goes in either the a or b position and 10 is the longest side so it will go in the c position.

8 0
3 years ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
3 years ago
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