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mylen [45]
3 years ago
12

What are the domain and range of f (x) = log x minus 5? domain: x > 0; range: all real numbers domain: x 5; range: y > 5 d

omain: x > 5; range: y > –5
Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0

Answer:

domain: x>5 Range: y>-5

Step-by-step explanation:

Elan Coil [88]3 years ago
3 0

Answer:

domain: x > 0; range: all real numbers

Step-by-step explanation:

edg 2020

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ASAP PLS HELP DUE TODAY. WILL GIVE BRAINLIEST IF A GOOD ANSWER EXPLENATION AND CORRECT ANSWER
aniked [119]

Answer:

7 + (-8)

Step-by-step explanation:

Given

7 - 8

(a): Write as additive inverse.

An additive inverse is of the form a + (-b)

In this case:

a = 7

b = -8

So, the expression can be represented as:

7 + (-8)

(b): Number line representation

When the expression in (a) is solved.

The result is:

7 - 8 = 7 + (-8) = -1

This means that the number line must accommodate 7 and -1.

Having said that, options (b) and (c) are out because their range is 0 to 15 and this excludes -1.

Option (d) is a wrong representation of 7 - 8

Hence, (a) is correct

7 0
3 years ago
A single letter from the word zookeeper is chosen. What is the probability of choosing k or an e? Express your answer as a fract
Westkost [7]

Answer:

4/9

Step-by-step explanation:

There are 9 letters in the word zookeeper.  4 of those letters are either a k or an e.  So the probability is 4/9.

4 0
3 years ago
Write the number 8.8 x 106 in standard form.
Musya8 [376]

Answer:

932.8

Step-by-step explanation:

Hope this helps!

3 0
2 years ago
when (2x - 3)^2 is subtracted from 5x^2, what is the result? And how can I show the answer? Thank you x
Leni [432]
5x^2 - (2x - 3)^2 = 
5x^2 - ((2x - 3)(2x - 3)) =
5x^2 - (4x^2 - 6x - 6x + 9) =
5x^2 - (4x^2 - 12x + 9) =
5x^2 - 4x^2 + 12x - 9 =
x^2 + 12x - 9 <===
3 0
3 years ago
Read 2 more answers
If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\

5 0
3 years ago
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