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olga55 [171]
4 years ago
13

In a dog show, there will be a gold, a silver, and a bronze medal awarded. There are

Mathematics
2 answers:
Monica [59]4 years ago
8 0
A lot of ways  medals can be awarded
VLD [36.1K]4 years ago
3 0
The correct answer is give the medal to the top 3 people


Hope this helps!
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Find the slope of the line that passes through (10,3) and (6,2)
8_murik_8 [283]

Answer:

.25

Step-by-step explanation:

y2-y1/x2-x1

m = -1 / -4 = 0.25

6 0
3 years ago
The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except -3. Which
Savatey [412]

Answer:

Third choice

Step-by-step explanation:

The domain of f(x) is the set of all real values except 7, i.e x\ne7

and the domain of g(x) is the set of all real values except -3, i.e x\ne -3

The domain of g\circ f is the set of all real numbers x in the domain of f  such that f(x) is in the domain of g(x).

However any numbers that are excluded from the domain of f must also be excluded from the domain of g\circ f.

Therefore the correct choice is all real values except x=7 and the x for which f(x) =7

6 0
4 years ago
Read 2 more answers
I really don't understand this. plzz help
Vsevolod [243]

Answer:

x = 25

Step-by-step explanation:

In any triangle, the sum of all 3 angles is ALWAYS 180 degrees. So we can make this into an equation.

4x + 2x+ 10 + x - 5 = 180

Now we combine the like terms.

7x + 5 = 180

Subtract 5 from both sides.

7x = 175

Now divide by 7 on both sides.

x = 25

8 0
4 years ago
Help. i need to graph this
photoshop1234 [79]

Answer:

ok 4 because its a even number would have to be so minus it 3 would go up and at number line 1

Step-by-step explanation:

8 0
4 years ago
This is really simple i just need help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Svetach [21]
It will stay the same.

\frac{2(4)}{4}  = 2
\frac{2(3)}{3}  = 2
\frac{2(2)}{2}  = 2
\frac{2(1)}{1}  = 2
No matter what you multiply 2 by, dividing it by the same number cancels it out, always leaving you with 2.
4 0
4 years ago
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