- The answer is A = x since the opposite sides of a rectangle are the same length.
- We'll have B = 9x+2 since this must add to x+4 to result in 10x+6. You could also do (10x+6) - (x+4) and you'll end up with 9x+2.
- On the far left side, (5x-3)+A = 5x-3+x = 6x-3. The far right side must add to this. So, x+C+x-2 = 6x-3 turns into C = 4x-1 after isolating C.
- Multiply out (5x-3) with (9x+2) to get the full area of 45x^2-17x-6. The steps are shown below
(5x-3)(9x+2)
5x(9x+2)-3(9x+2)
45x^2+10x-27x-6
45x^2-17x-6
You could also use the FOIL rule to get this answer. The box method is another alternative.
<span>r²sin²θ = 16rcosθ </span>
<span>rsin²θ = 16cosθ </span>
<span>r = 16cosθ / sin²θ </span>
<span>r = 16cotθcscθ</span>
Answer:
Lil Nas X - THAT’S WHAT I WANT..................
Step-by-step explanation:
Answer:

Step-by-step explanation:
So, the function, P(t), represents the number of cells after t hours.
This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.
C)
So, we are given that the quadratic curve of the trend is the function:

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:
![\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5BP%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2-9.28t%2B16.43%5D)
Expand:
![P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]](https://tex.z-dn.net/?f=P%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B-9.28t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B16.43%5D)
Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:
![P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]](https://tex.z-dn.net/?f=P%27%28t%29%3D6.10%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D-9.28%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5D)
Differentiate. Use the power rule:

Simplify:

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

Multiply:

Subtract:

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.
And we're done!