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WARRIOR [948]
3 years ago
9

Please Help: I don't understand this???

Mathematics
1 answer:
iragen [17]3 years ago
8 0

Try and ask my sister.

Her user is Sadie8D


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What is the solution of the equation sqrt 2 x+4-sqrt x=2
ivann1987 [24]
There are 2 answers to this 

x=0 
x=16
3 0
3 years ago
Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1
eimsori [14]

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.)  f(x) = -12x^2+3x+1 \\

b.)  f(x) = 3x^2+11x-12 \\

c.)  f(x) = 12x^2+3x+3\\

d.)  f(x) = 3x -12.

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

brainly.com/question/2263981

8 0
2 years ago
Solve the inequality.<br> 6+x&gt;56+x&gt;5
weqwewe [10]

Answer:

X>50

X>-51

Step-by-step explanation:

6+x>56

56+x>5

separate the equation into different equations by the sign

I) 6+x>56

x>56-6

x>50

ii) 56+x>5

x>5-56

x>-51

4 0
2 years ago
Explain WHAT WOULD HAPPEN TO motion IF friction DID NDT EXIST.
MA_775_DIABLO [31]

Answer:

If friction did not exist, it would be hard for us to slow down in running, or putting breaks on a car, and more!

If friction did not exist, your car will slide down the road even if you try your best to put the brakes on a car. Friction is a very important force to slow down things that are moving very fast

Step-by-step explanation:

Hoped this helped.

GeniusUser

5 0
2 years ago
The box plots shown represent two data sets. Use the box plots to compare the data sets.
DiKsa [7]

Answer:

Same in both sets

Minimum , medium

Different

IQR

Cannot tell

mode, mean

Step-by-step explanation:

8 0
2 years ago
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