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3 years ago

Which of the following provides an object with rotational symmetry?

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

It’s the one that looks like a star a little!! :D

Nookie1986 [14]3 years ago

7 0

Answer: Choice C) Star shaped symbol

We can rotate the star symbol 90 degrees to have it line up with its original image. The before and after images would be identical after doing such a rotation. So this figure has rotational symmetry.

The other figures would change if we rotated them some angle x such that $0 < x < 360$ , so they do not have rotational symmetry.

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Which of the following is a radical equation? X+ V5 = 12 x² = 16 3+ x^7=13 7-14

MrRissso [65]

The second one is the correct answer

5 0

3 years ago

Using algebra, solve the inequality writing your answer in set notation. x²-x> 20

Xelga [282]

Answer:

(-4, 0) U (1, ∞)

Step-by-step explanation:

Set each factor EQUAL to zero to find the zeroes (since it is not actually equal to zero, you will use an open circle when graphing and an open bracket when writing in interval notation).

x = 0 x-1 = 0 x + 4 = 0

x = 1 x = -4

Next, choose a value to the far left, between each of the zeroes, and to the far right to evaluate if it makes a true statement when input into the given inequality.

far left (I choose -5): -5(-5 - 1)(-5 + 4) > 0 → (-)(-)(-) > 0 → negative > 0 FALSE

- 4 to 0 (I choose -2): -2(-2 - 1)(-2 + 4) > 0 → (-)(-)(+) > 0 → positive > 0 TRUE

0 to 1 (I choose 0.5): .5(.5 - 1)(.5 + 4) > 0 → (+)(-)(+) > 0 → negative > 0 FALSE

far right (I choose 2): 2(2 - 1)(2 + 4) > 0 → (+)(+)(+) > 0 → positive > 0 TRUE

3 0

10 months ago

Problem1 The behavior of a physical system can be described by the following first order differential equation: dy/dt=2y +t^2

daser333 [38]

Answer:

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$ .

Step-by-step explanation:

Using first order linear differential equation:

$\dfrac{\mathrm{d} y}{\mathrm{d} t} = 2y + t^2$

$\frac{\mathrm{d} y}{\mathrm{d} t} - 2y =t^2$

finding integrating factor:

I.F = $e^{\int -2dt}$

I.F = $e^{-2t}$

now,

$y = \dfrac{1}{IF}(\int t^2dt+ c )$

$y = \dfrac{1}{e^{-2t}}(\int t^2dt+ c )$

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

hence the solution is

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

8 0

3 years ago

If there are 16 cups in one gallon, how many cups are there in 3 gallons? How many cups are in 5 gallons? Total points with expl

Zigmanuir [339]

If there are 16 cups in one gallon, each gallon u add 16. If you have 3 gallons you add 16 3 times. So to get your answer you multiply 16 by three which is 48 cups.

6 0

2 years ago

Read 2 more answers

Desmond's Desserts made a batch of fresh scones with 2/3 of a pound of butter and 1/2 of a

NemiM [27]

$\frac{1}{6}$ or 0.167 pounds more butter was used than sugar

Solution:

Given that, Desmond's Desserts made a batch of fresh scones with 2/3 of a pound of butter and 1/2 of a pound of sugar

To find: Amount of butter used than sugar

From given information,

$\text{Butter used} = \frac{2}{3} \text{ pound }$

$\text{Sugar used } = \frac{1}{2} \text{ pound }$

To find how much butter is used than sugar, find the difference between them

$Difference = Butter\ used - Sugar\ used$

$Difference = \frac{2}{3} - \frac{1}{2}\\\\Difference = \frac{2 \times 2-1 \times 3}{3 \times 2}\\\\Difference =\frac{4-3}{6}\\\\Difference =\frac{1}{6} = 0.167\\\\$

Thus $\frac{1}{6}$ or 0.167 pounds more butter was used than sugar

5 0

3 years ago