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Nitella [24]
2 years ago
13

Change 1/2 as a fraction

Mathematics
2 answers:
dimaraw [331]2 years ago
8 0

Answer:

0.50 ,1/2 as a fraction 1/2

Step-by-step explanation:

Valentin [98]2 years ago
7 0

Hey there!

1/2 is already a fraction but they are numerous of fractions that are equivalent to it!


The decimal form of 1/2 is: 0.50

Here’s some of them…..

= 2/4

= 3/6

= 4/8

= 5/10

Good luck on your assignment & enjoy day!

~Amphitrite1040:)

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Suppose it is known that 8 out of the 20 teams in the sample had a season winning percentage better than 0.500.
Ganezh [65]

Answer:

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that n = 20, \pi = \frac{8}{20} = 0.4.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

3 0
3 years ago
Help me with this answer
Hatshy [7]

Can you please put your question first???

In comment box:)

8 0
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2 years ago
Ice cream cost $4.96 for 4 litres how much for 6 litres
aivan3 [116]

Answer:

$7.44

Step-by-step explanation:

$4.96/ 2= 2.48

$2.48 X 3 = 7.44

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