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Dominik [7]
3 years ago
14

17. The length of a rectangle is 3 inches greater than its width. The perimeter is 28 inches.

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

\boxed{ \bold{ \sf{ width \: of \: a \: rectangle = 5.5 \: inches}}}

\boxed{ \bold{ \sf{length \: of \: a \: rectangle =8.5 \ \: \:  inches}}}

Step-by-step explanation:

Let the width of a rectangle be 'w'

Length of a rectangle = w + 3

Perimeter of a rectangle = 28 inches

To find : dimensions of the rectangle ( length and width )

<u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>(</u><u> </u><u>w</u><u> </u><u>)</u><u> </u>

\boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}

\dashrightarrow{ \sf{28 = 2(w + 3 + w)}}

\dashrightarrow{ \sf{28 = 2(2w + 3)}}

\dashrightarrow{ \sf{28 = 4w + 6}}

\dashrightarrow{ \sf{4w + 6 = 28}}

\dashrightarrow{ \sf{4w = 28 - 6}}

\dashrightarrow{ \sf{4w = 22}}

\dashrightarrow{ \sf{ \frac{4w}{4}  =  \frac{22}{4} }}

\dashrightarrow{ \sf{w = 5.5 \: inches}}

Width of a rectangle = 5.5 inches

<u>Now</u><u>,</u><u> </u><u>replacing</u><u> </u><u>/</u><u> </u><u>substit</u><u>uting</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>w</u><u> </u><u>in</u><u> </u><u>order</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u><u> </u>

\sf{ length = 3 + w}

\dashrightarrow{ \sf{length = 3 + 5.5}}

\dashrightarrow{ \sf{length = 8.5  \: \: inches}}

Length of a rectangle = 8.5 inches

Hope I helped!

Best regards! :D

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